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1Z0-804 - Java SE 7 Programmer II - Dump Information

Vendor : Oracle
Exam Code : 1Z0-804
Exam Name : Java SE 7 Programmer II
Questions and Answers : 150 Q & A
Updated On : January 19, 2018
PDF Download Mirror : 1Z0-804 Brain Dump
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1Z0-804 Questions and Answers

1Z0-804

Gets an object for the given key from this resource bundle or one of its parents.


QUESTION: 140

Given:


What is the result of invoking Car's scop method?


  1. Both vehicles and Motorized’s stop methods are invoked.

  2. Vehicles stop method is invoked.

  3. Motorized’s stop method is invoked-

  4. The implementation of the Car’s stop determines the behavior.

  5. Compilation fails.


Answer: D


Explanation:

The Car class is implementing the methods. Methods are not implemented in interfaces.


QUESTION: 141

Given:

interface Rideable {

public String ride() { return "riding "; }

}

class Horse implements Rideable {

public String ride() { return "cantering "; }

}

class Icelandic extends Horse implements Rideable { public String ride() { return "tolting "; }

}

class Test {

public static void main(String[] args) { Rideable r1 = new Icelandic(); Rideable r2 = new Horse();

Horse h1 = new Icelandic(); System.out.println(r1.ride() + r2.ride() + h1.ride());

}

}

What is the result?


  1. riding riding tolting

  2. riding riding cantering

  3. tolting cantering tolting

  4. tolting cantering cantering

  5. Compilation fails.

  6. An exception is thrown at runtime.


Answer: E


Explanation:

The compilation fails at: interface Rideable {

public String ride() { return "riding ";}

}

Error due to: interface methods cannot have body.


QUESTION: 142

You have been asked to create a ResourceBundle file to localize an application. Which code example specifies valid keys menu1 and manu2 with values of File Menu and ViewMenu?


  1. <key name ="menu1">File Menu</key>

    <key name ="menu1">View Menu</key>

  2. <key> menu1</key><File Menu>File Menu </value>

    <key> menu1</key><File Menu>View Menu </value>

  3. menu1m File menu, menu2, view menu

  4. menu1 = File Menu menu2 = View Menu


Answer: D


Explanation:

A properties file is a simple text file. You can create and maintain a properties file with just about any text editor. You should always create a default properties file. The name of this file begins with the base name of your ResourceBundle and ends with the .properties suffix. In the PropertiesDemo program the base name is LabelsBundle. Therefore the default properties file is called LabelsBundle.properties. The following examplefile contains the following lines:

# This is the default LabelsBundle.properties file s1 = computer

s2 = disk

s3 = monitor s4 = keyboard

Note that in the preceding file the comment lines begin with a pound sign (#). The other lines contain key-value pairs. The key is on the left side of the equal sign and the value is on the right. For instance, s2 is the key that corresponds to the value disk. The key is arbitrary. We could have called s2 something else, like msg5 or diskID. Once defined, however, the key should not change because it is referenced in the source code. The values may be changed. In fact, when your localizers create new properties files to accommodate additional languages, they will translate the values into various languages.


QUESTION: 143

Given:

interface Rideable { String ride() ;

}

class Horse implements Rideable { String ride() { return "cantering "; }

}

class Icelandic extends Horse { String ride() { return "tolting "; }

}

class Test {

public static void main(String[] args) { Rideable r1 = new Icelandic(); Rideable r2 = new Horse();

Horse h1 = new Icelandic(); System.out.println(r1.ride() + r2.ride() + h1.ride());

}

}

What is the result?


  1. tolting cantering cantering

  2. cantering cantering cantering

  3. compilation fails

  4. an exception is thrown at runtime


Answer: A


QUESTION: 144

Given:

public class SleepOtherThread {

public static void main(String[] args) throws InterruptedException { Runnable r = new Runnable() {

public void run() { System.out.print(Thread.currentThread().getName());

}

};

Thread t1 = new Thread(r, "One "); t1.start();

t1.sleep(2000);

Thread t2 = new Thread(r, "Two "); t2.start();

t2.sleep(1000); System.out.print("Main ");

}

}

What is the most likely result?


  1. Main One Two

  2. Main Two One

  3. One Two Main

  4. One Main Two

  5. Two Main One


Answer: C


QUESTION: 145

Which two are valid initialization statements?


  1. Map<String, String> m = newSortedMap<String, String>();

  2. Collection m = new TreeMap<Object, Object>();

  3. HashMap<Object, Object> m = newSortedMap<Object, Object>();

  4. SortedMap<Object, Object> m = new TreeMap<Object, Object> ();

  5. Hashtablem= new HashMap();

  6. Map<List, ArrayList> m = new Hashtable<List, ArrayList>();


Answer: D, F


QUESTION: 146

Which four are syntactically correct?


  1. package abc; package def; import Java.util . * ; public class Test { }

  2. package abc; import Java.util.*; import Java.util.regex.* ;

    public class Test { }

  3. package abc; public class Test {} import Java.util.* ;

  4. import Java.util.*; package abc; public class Test {}

  5. package abc; import java.util. *; publicclassTest{}

  6. publicclass Test{} package abc; importjava.util.*{}

  7. import java.util.*; public class Test{}

  8. package abc; public class test


Answer: B, E,G , H


QUESTION: 147

Given the code fragment: public class Test {

public static void main(String[] args) { Path dir = Paths.get("D:\\company");

//insert code here. Line *** for (Path entry: stream) {

System.out.println(entry.getFileName());

}

} catch (IOException e) {

System.err.println("Caught IOException: " + e.getMessage());

}

}

Which two try statements, when inserted at line ***, enable you to print files with the extensions.java, .htm, and .jar.


  1. try (DirectoryStream<Path> stream = Files.newDirectoryStream(dir,"*.{java, htm,jar}")){

  2. try (DirectoryStream<Path> stream = Files.newDirectoryStream(dir,"*. [java, htm, jar]")) {

  3. try (DirectoryStream<Path> stream = Files.newDirectoryStream(dir,"*.{java*, htm*, jar*}")) {

  4. try (DirectoryStream<Path> stream = Files.newDirectoryStream(dir,"**.{java, htm, jar}")) {


Answer: A, D


Explanation:

"*. {java, htm, jar}and "**. {java, htm, jar}will match any file with file endings java, htm, or jar.


QUESTION: 148

Given:

import java.io.File; import java.nio.file.Path;

public class Test12 {

static String displayDetails(String path, int location) { Path p = new File(path).toPath();

String name = p.getName(location).toString(); return name;

}

public static void main(String[] args) { String path = "project//doc//index.html"; String result = displayDetails(path,2); System.out.print(result);

}

}

What is the result?


  1. doc

  2. index.html

  3. an IllegalArgumentException is thrown at runtime.

  4. An InvalidPthException is thrown at runtime.

  5. Compilation fails.


Answer: B


QUESTION: 149

Given the code fragment: public void otherMethod() { printFile("");

}

public void printFile(String file) {

try (FileInputStream fis = new FileInputStream(file)) { System.out.println (fis.read());

} catch (IOException e) { e.printStackTrace();

}

Why is there no output when otherMethod is called?


  1. An exception other than IOException is thrown.

  2. Standard error is not mapped to the console.

  3. There is a compilation error.

  4. The exception is suppressed.


Answer: D


Explanation:

The code compiles fine

The line

FileInputStream fis = new FileInputStream(file)) will fail at runtime since file is an empty string. Note:

public void printStackTrace()

Prints this throwable and its backtrace to the standard error stream.


QUESTION: 150

Given the code fragment:

public void ReadFile (String source) { char[] c = new char [128];

int cLen = c.length;

try (FileReader fr = new FileReader (source)) { int count = 0;

int read = 0;

while ((read = fr.read(c)) != -1) { count += read;

}

System.out.println("Read: " + count + " characters.");

} catch (IOException i) {

}

What change should you make to this code to read and write strings instead of character arrays?


  1. ChangeFileReader to Readers.

  2. ChangeFileReader to DataReader.

  3. ChangeFileReader to File.

  4. ChangeFileReader to BufferReader.


Answer: D


Explanation:

public class BufferedReader extends Reader Read text from a character-input stream, buffering characters so as to provide for the efficient reading of characters, arrays, and lines. The buffer size may be specified, or the default size may be used. The default is large enough for most purposes.


Oracle 1Z0-804 Exam (Java SE 7 Programmer II) Detailed Information

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